If the length L in the conduction problem is doubled to 0.60 m, what is the new Q/t?

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Multiple Choice

If the length L in the conduction problem is doubled to 0.60 m, what is the new Q/t?

Explanation:
The main idea is that heat conduction through a rod follows Q/t = (k A ΔT)/L, so the transfer rate is inversely proportional to the length. If you double the length, you halve Q/t (everything else kept the same). Since the length is doubled to 0.60 m, the new rate is half the original rate. If the original Q/t was 80 W, the new rate becomes 40 W, which matches the given answer.

The main idea is that heat conduction through a rod follows Q/t = (k A ΔT)/L, so the transfer rate is inversely proportional to the length. If you double the length, you halve Q/t (everything else kept the same). Since the length is doubled to 0.60 m, the new rate is half the original rate. If the original Q/t was 80 W, the new rate becomes 40 W, which matches the given answer.

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